![]() Where the indexed A-s denotes the surface area of consecutive lateral faces. This way, we arrive at the not-so-scary-anymore formula: But worry not, my friend! As long as we know a and the pyramid height, we can calculate h using the Pythagorean theorem. We usually know a well enough, but h can get a little tricky. Let us now take care of the other faces of the pyramid and find the lateral area, A_l.Īt first glance, you might think that we might have a problem here since the lateral edges are triangles, whose surface area formula is area = (a × h) / 2, where a is the base length and h is the height projected onto that a, also called the slant of the pyramid. Observe that when we asked ourselves how to find the volume of a rectangular pyramid above, we had to know the base area of the pyramid, i.e., the value A_b. It seems that we weren't so far from the actual answer with our initial " probably a lot." Or roughly 3,390,339 cubic yards if you prefer imperial. ![]() ![]() Using the above square pyramid volume formula, we find that: Now we're left with the most fun part, counting! Yay, right? Right.? Moreover, we will need the height of the pyramid, so once again, we use our favorite search engine and find that it is 147 meters (or 280 Egyptian Royal cubits). (Also, in this case, please let us know how you do that pose that is on all your hieroglyphs because some of us have been trying to bend our hands that way since primary school, and we just can't get it right.) Otherwise, let's use the good old metric system – 230 meters. If you happen to be an ancient Egyptian, this is equal to 440 Egyptian Royal cubits. As you may know, the Great Pyramid of Giza's base is a square, so we will use the well-known formula of area = a × a, where a is the base side length. Note that we will need to know the base area. Volume = (base_area × pyramid_height) / 3. Let's begin with a question that may have bugged you for years: what is the volume of the Great Pyramid of Giza? Unfortunately, " probably a lot" is often not a sufficient answer, so let's take a look at the square pyramid volume formula to see what we're dealing with:
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